Suppose that event E 1 can result in any one of n( E 1) possible outcomes and for each outcome of the event E 1, there are n( E 2) possible outcomes of event E 2. Altogether there areĮ 2 = "choose jeans" Multiplication Rule in General We have `2` t-shirts and with each t-shirt we could pick `4` pairs of jeans. How many different combinations can you choose? Answer Say the only clean clothes you've got are `2` t-shirts and `4` pairs of jeans. Now consider the case when two events E 1 and E 2 are to be performed and the events E 1 and E 2 are independent events i.e. Where E 1 ∩ E 2 means "the intersection of the sets E 1 and E 2". N( E) = n( E 1) + n( E 2) = 7 + 2 = 9 Part (b)Į 1 = Įvents E 1 and E 2 are not mutually exclusive. Events E 1 and E 2 are mutually exclusive.
0 Comments
Leave a Reply. |